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Menampilkan postingan dari Juli, 2015

Pembahasan Soal Fungsi Matematika

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1.       G(x) = x 2 – x + 3       Fog)(x) = 3x 2 – 3x + 4       F(x-2) = ....     

Function Composition

WELCOME EVERYBODY! ^^ TODAY I'LL POST ABOUT FUNCTION COMPOSITION, HIGHSCHOOL GRADE. THIS MATERIAL IS SO CHALLENGING. BUT YOU CAN GET USED TO IT! ^^   The Basic Characteristic Of Function Compositions        I.           Composition Function is : ( f o g ) (x) =   f( g(x) )   = f composition g for x Example ^^ :

How To Determine Circle Equations

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II.         LOOK FOR CIRCLE EQUATIONS ^^          Now the reverse, how to find the equation of the circle if known its center and radius.      Determine the equation of the circle below : 1.      Center (0,0) r = 3 2.      Center (-3, -1) r = 6 3.   Point (6, 8) i s on a Circle A the center is (0.0). The circle equations?              Answer     1. For the center (0,0) The circle equation   : x² + y² = r²      o    So, the equation circle =  x² + y² = 3

Cara Menentukan Persamaan Lingkaran

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Menentukan persamaan lingkaran jika diketahui pusat dan jari-jari.      Tentukan persamaan lingkaran berikut : 1. Pusat (0,0) Jari-jari = 3 2. Pusat (-3, -1) Jari-jari = 6 3. Titik (6, 8 ) melewati lingkaran A yang pusatnya (0,0). Persamaan Lingkaran A?

To Know kinds of Circle Equations, Look For Center and Radius

     THERE ARE 3 TYPES OF CIRCLE EQUATIONS: 1.     The center (0,0) equation : x² + y² = r²      2.     The center (a, b) equation 1 : (x-a)² + (y-b)² =r² 3.      The center (a, b) equation 2 :   x² + y² + Ax  + By + C = 0        atau                                              x² + y² - 2ax – 2by + a 2   + b 2 - r² = 0      Description :     -     a,b  =          center of circle -         x,y =          a point on the circle -       ...

Mengetahui Jenis-jenis Persamaan Lingkaran, Mencari Pusat dan Jari - Jarinya

     ADA 3 JENIS PERSAMAAN LINGKARAN : 1.      Pusat (0,0) persamaan : x² + y² = r²      2.      Pusat (a,b) persamaan 1 : (x-a)² + (y-b)² =r² 3.      Pusat (a,b) persamaan 2 :   x² + y² + Ax   + By + C = 0        atau                                              x² + y² - 2ax – 2by + a 2   + b 2 - r² = 0      Keterangan :     -     a,b =          pusat lingkaran -         x,y =          suatu titik di lingkaran -         r ...