WELCOME EVERYBODY! ^^ TODAY I'LL POST ABOUT FUNCTION COMPOSITION, HIGHSCHOOL GRADE. THIS MATERIAL IS SO CHALLENGING. BUT YOU CAN GET USED TO IT! ^^
The Basic Characteristic Of Function Compositions
I. Composition Function is :
( f o g ) (x) = f( g(x) )
= f composition g for x
Example
^^ :
- f(x) = 5x – 4 and g(x) = 2x + 8
( f o g )? = f( g(x) )
f( 2x + 8 ) -----> 5( 2x + 8 ) – 4 ---> 10x + 40 – 4 ----> 10x + 36as you can see above ...Basically change the X value of F(x) into g(x) so become f( g(x) ) = f( 2x + 8 ) and because the F(x) = 5x – 4 logically F( 2x + 8) = 5( 2x + 8) – 4 ^^ -----> 10x + 8How about ( g o f )?Value still the same : f(x) = 5x – 4 and g(x) = 2x + 8( g o f ) = g( f(x) )g(5x -4) ------> 2(5x – 4) + 8 -----> 10x – 8 + 8 = 10x ^^
The answer is different so this is mean ( f o g ) IS NOT THE SAME AS (
g o f )
2. F(x) = x2 + 2x – 3 and g(x) = 5x -1
( f o g )? = f( g(x) )f(5x – 1) ------> (5x – 1)2 + 2(5x – 1) – 3-------> 25x – 10x + 1 + 10x – 2 - 3-------> (25x – 4) the answer!How about ( g o f )(-1) ?Value still the same : F(x) = x2 + 2x – 3 and g(x) = 5x - 1( g o f ) = g( f(x) ) ---> ( g o f )(-1) = g( f(-1) )5(x2 + 2x – 3) – 1 -----> What was asked is ( g o f )(-1) . so change the x from ( f(x) )into value -1 FIRST like this -----> 5((-1)2 + 2(-1) – 3) – 1---> 5(1 -2 – 3) – 1---> 5(-4) – 1 = -21 the answer!
Here some other Characteristic ^^ :
- Function Compositions is NOT commutative
2. Function Compositions IS Associative
( ( f o g ) o h)(x) = ( f o (g o h ) )(x)
3. There is Identity Function I(x) = x
so ---> ( f o I )(x) = ( I o f )(x) = f(x)
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