Pembahasan Soal Fungsi Matematika

1.      G(x) = x² – x + 3

      Fog)(x) = 3x² – 3x + 4

      F(x-2) = ....

    
  F(g(x)) = 3x² – 3 + 4

      F(x² – x + 3) = 3x² – 3 + 4

      F(x² – x + 3) = 3x² – 3 + 4

      F(x² – x + 3) = 3(x² – x + 3) – 5

      F(x) = 3x – 5

  F(x -2) = 3(x-2) – 5

  F(x-2) = 3x – 11

2.      

3.      F(x) = 6x – 3 . G(x) = 5x + 4. (Fog) (a) = 81. A=?

( F o g ) (x) = f( g(x) )

                       = 6(5x + 4 ) – 3

F o g (x) = 30x + 24 – 3 = 30x + 21 --- > (Fog) (a) = 30a + 21

(Fog) (a) = 81

30a + 21 = 81

30x = 60

A = 2