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  https://www.studyinjapan.go.jp/en/planning/scholarships/mext-scholarships/examination.html Jawaban dari : Aplikasi gauth pro ### Question 1 An object of mass $m$ is launched horizontally with a speed $v$ at a height of $h$ above the ground level as shown in Fig. 1-1. Let $\theta$ be the impact angle to the ground and $g$ be the acceleration of gravity. Find the formula of $\tan\theta$. ### Answer

  https://www.studyinjapan.go.jp/en/planning/scholarships/mext-scholarships/examination.html Jawaban dari : Aplikasi gauth pro This is a basic high-school/introductory mechanics problem. Since the surface is frictionless, the object experiences a constant net force, so Newton’s second law and uniformly accelerated motion equations can be used.

https://www.studyinjapan.go.jp/en/planning/scholarships/mext-scholarships/examination.html Jawaban dari : Aplikasi gauth pro Based on the velocity-time graph provided in Fig. 1-1, the distance traveled by the car is equal to the **area under the curve**. The shape formed is a **trapezoid**. ### **Method 1: Using the Trapezoid Area Formula** The area $A$ of a trapezoid is given by: $$A = \frac{1}{2} \times (\text{sum of parallel sides}) \times \text{height}$$ 1. **Bottom base ($b_1$):** The total time from start to stop is $80 - 0 = 80 \text{ s}$. 2. **Top base ($b_2$):** The time during which the car maintains constant velocity is $40 - 20 = 20 \text{ s}$. 3. **Height ($h$):** The maximum velocity reached is $60 \text{ m/s}$. $$\text{Distance} = \frac{1}{2} \times (80 + 20) \times 60$$ $$\text{Distance} = \frac{1}{2} \times 100 \times 60$$ $$\text{Distance} = 50 \times 60 = 3000 \text{ m}$$ --- ### **Method 2: Summing Individual Parts** You can also split the shape into two triangle...

https://www.studyinjapan.go.jp/en/planning/scholarships/mext-scholarships/examination.html Jawaban dari : Aplikasi gauth pro   Based on the provided velocity-time graph (Fig. 1-1), we can find the total distance traveled by calculating the area under the curve . The graph forms a trapezoid . The area of a trapezoid is given by the formula: \text{Area} = \frac{1}{2} \times (\text{\sum of parallel sides}) \times \text{height}

https://www.studyinjapan.go.jp/en/planning/scholarships/mext-scholarships/examination.html Answered by https://math-gpt.org  1Get UnlimitedGet MathGPT UnlimitedSolve the above problem.I don’t see the math problem in your message. Please paste the problem statement or upload the image, and I’ll solve it step by step. Create Practice QuestionCreate Practice TestCreate MathGPT VideoSolve the above problem.(6) Sequence The sequence is $1,\ 4,\ 10,\ 19,\ 31,\ldots$ Find the differences: \begin{array}{c|ccccc} \text{Term} & 1 & 4 & 10 & 19 & 31\\ \hline \text{First difference} & & 3 & 6 & 9 & 12\\ \text{Second difference} & & & 3 & 3 & 3 \end{array}

https://www.studyinjapan.go.jp/en/planning/scholarships/mext-scholarships/examination.html Answered by https://math-gpt.org/   (6) Sequence The sequence is 1 ,   4 ,   10 ,   19 ,   31 , … 1,\ 4,\ 10,\ 19,\ 31,\ldots 1 , 4 , 10 , 19 , 31 , … Find the differences: Term 1 4 10 19 31 First difference 3 6 9 12 Second difference 3 3 3 \begin{array}{c|ccccc} \text{Term} & 1 & 4 & 10 & 19 & 31\\ \hline \text{First difference} & & 3 & 6 & 9 & 12\\ \text{Second difference} & & & 3 & 3 & 3 \end{array} Term First difference Second difference ​ 1 ​ 4 3 ​ 10 6 3 ​ 19 9 3 ​ 31 12 3 ​ ​ Since the second difference is constant, the sequence is quadratic. The first difference before the first term is 0 0 0 , so the n n n -th term can be found by adding the differences: a n = 1 + 3 ( 1 + 2 + ⋯ + ( n − 1 ) ) . a_n=1+3(1+2+\cdots +(n-1)). a n ​ = 1 + 3 ( 1 + 2 + ⋯ + ( n − 1 )) . Using 1 + 2 + ⋯ + ( n −...